#1
4x+1+3=0
#2
2Y+7+4=Y
Can some one help me solve these two poblems
They have the squared symbol in front of them
2006-11-01 11:09:43 · 4 answers · asked by angel l 1 in Education & Reference ➔ Homework Help
#1
4x+1+3=0
4x+4=0
4x=-4
x=-1
#2
2y+7+4=y
2y+11=y
y=-11
2006-11-01 11:17:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
4x + 1 + 3 = 0
4x + 4 = 0
4x/4 + 4/4 = 0
x +1 = 0
x = -1
2y + 7 + 4 = y
2y + 11 = y
2y +11 - 11 = y - 11
2y = y - 11
2y - y = y - 11 - y
y = -11
2006-11-01 19:34:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4x + 1 + 3 = 0
4x + 4 = 0
4x + 4 - 4 = -4
4x = -4
4x/4 = -4/4
x = -1
2y + 7 + 4 = y
2y + 11 = y
2y - y + 11 = y - y
y + 11 = 0
y + 11 - 11 = - 11
y = -11
2006-11-01 19:26:35 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
#1 = 1
#2= 6
2006-11-01 19:15:41 · answer #4 · answered by Brittany W 1 · 0⤊ 1⤋