Chemistry help needed!!!?

Question

Questions:

1- Write the electron configuration for an atom that has 13 electrons.

2- Write the electron configuration for an atom that has 33 electrons.

Answer 1

I'm going to cheat a little bit in both cases by just referring back to the nearest noble gas. That itself may be acceptable for your purposes (it's how most chemists list them because things past that point are usually of no interest)... if you need, I'll pass on the underlying noble gas configuations too.

13: [Ne] 3s2 3p1
33: [Ar] 4s2 3d10 4p3

Basically, the electrons usually fill up the shells just as you see the elements arranged on the periodic table. Group 1 and 2 (the two columns on the left) are the s shell, and the number of the s shell is indicated by the row number. Group 13 through 18 (the six columns on the right) are the p shell; its number is also the same as the row number. The middle stretch are d orbitals, and they're so expensive energetically that the ones on each row are orbitals from one shell down. That chart is handy for all kinds of things!

Hope that helps!

Answer 2

thats what we are doing now.

i hate chemistry! argggg!!!!

btw have you tried the digonal rule to get the electron comfigurations?
from bottom to top.
(and you keep going till you get to 7- all of them to 7 are the same as 4)
4s^2 4p^6 4d^10 4f^14
3s^2 3p^6 3d^10
2s^2 2p
1s^2

sp after you do that, you cross them like 1s^2 would be one line, and then 2p and 3s^2 would be another line. and so on.

so when you write them just follow the lines in order, and add the powers to get to 33.

Answer 3

For the first atom: 1s2 2s2 2p6 3s2 3p1

For the second atom: 1s2 2s2 2p6 3s2 3p6 3d104s2 4p3

Answer 4

1) 1s2 2s2 2p6 3s2 3p1

2) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3