2006-11-01 10:21:51 · 17 answers · asked by cmjokinen 2 in Entertainment & Music ➔ Television
bob barker cant be replaced i wont watch it anymore when he leaves
but its not going to be rickki lake!! god i hated that special with her on it
rickki lake wont be the new host!
and i will make sure of that
2006-11-01 10:30:12 · answer #1 · answered by Anonymous · 2⤊ 2⤋
The Price is Right will retire with Bob. I just can't see people still watching it without their beloved Bob Barker. The show would just not be the same!
2006-11-01 10:30:11 · answer #2 · answered by redcherri817 3 · 1⤊ 1⤋
The decision hasn't been made yet. The news that Barker was quitting came only yesterday.
2006-11-01 10:24:59 · answer #3 · answered by WC 7 · 1⤊ 1⤋
No one can "replace" him. CBS can find another host, but no matter who it is, they won't be another Bob Barker.
2006-11-01 10:23:54 · answer #4 · answered by missourim43 6 · 4⤊ 0⤋
Johnny Knoxville
hahaha
2006-11-01 10:29:42 · answer #5 · answered by girl909e 2 · 3⤊ 2⤋
*Sniff* *Sniff* I never got to come on down. But Bob deserves a good retirement. I mean he is like in his 80's. I hope it is someone good. It will be hard to fill his shoes.
2006-11-01 10:33:31 · answer #6 · answered by Laura L. 2 · 3⤊ 1⤋
I think the show will be heading down in flames after he leaves they probably should just work on a new show to replace it
2006-11-01 10:44:04 · answer #7 · answered by nascarfan1189 2 · 0⤊ 1⤋
HE'S QUITTING?!!! I mean I knew it would have to happen some time, either he quits or dies, but that's sad.... If that happens they need to retire Price is Right in his honor! No one should ever be allowed to take his place, and nobody in the world could ever replace him.... That's so sad.....
2006-11-01 10:28:50 · answer #8 · answered by Rick R 5 · 1⤊ 2⤋
Dick Clark
They both have not changed a bit in the last 100 years!!!
2006-11-01 10:47:25 · answer #9 · answered by Sunshine 4 · 1⤊ 3⤋
dont know but who ever it is is going to have some big shoes to fill
2006-11-01 10:24:32 · answer #10 · answered by ali 3 · 3⤊ 0⤋