help graphing x-4y+4=12?

Question

i need help graphing.x-4y=4=12 i need like step by step work through. and what will the points end up being on the coordinate plane?..thanks

Answer 1

x-4y+4=12

you want to get it in y= mx + b form

so switch the 4y and the 12

x + 4 -12 = 4y
x - 8 = 4y

now divide by 4

(1/4)x -2 = y

so the slope is 1/4 and it crosses the y axis at -2

some points are
(0, -2)
(-4, -3)
(-8, -4)
(4, -1)
(8, 0)
(12, 1)

hope this helped
best of luck

Answer 2

Al right, the first thing to do is put it in standard linear form. (Get y alone on one side of the equation)

x - 4y + 4 = 12
Subtract 12 from both sides
x - 4y - 8 = 0
Add 4y to both sides
x - 8 = 4y
Divide both sides by 4
.25x - 2 = y

This form should look familiar. Now you can plug in at least 2 (3 is better) values for x to find the y. The graph is a line, so you can simply connect-the-dots. It should be a gentle upward slope crossing the y-axis at -2 and crossing the x-axis at .5. I hope i've helped. Good Luck!

Answer 3

For a start you should subtract 4 from both sides to get
x - 4y = 8

Usually we pick values of x and work out the y values which they give, but in this case it may be easier to make x the subject of the equation by adding 4y to both sides:
x = 8 + 4y

Then you just pick values of y and work out the corresponding x values, then plot the points on the plane. e.g.
y = 0 gives
x = 8 + 4*0
= 8

The corresponding point is on the x axis (because y = 0) where
x = 8

Pick y = 1, giving
x = 8 + 4*1
= 12
so you mark the point 12 units right and 1 unit up.

Pick y = -1, and you get a point not quite so far out.

Pick y = -3, get x = -4, and mark the point 4 units left and 3 down.

Work out y = -2 for yourself.

All these points will be in a straight line if you calculate and plot correctly.

Answer 4

I think the easiest way is to solve for y and either plug in values for x, then get y, or use the slope intercept method. That's not as easy if you have fraction.

x-4y +4=12
x-4y=8
-4y=-x+8
y=1/4(x) -2

I would let x=0, so y=-2 Plot (0,-2)
x=4 (so I wouldn't have any fractions), y=1-2 or -1 Plot (4,-1)
x=8, so y=0, Plot (8,0)

If these 3 points lie on a straight line, you are correct. If not, you've made a mistake in at least one of them. Hope I've helped

Answer 5

You need to get it in the form y= a*x+b

1. Bring the 12 across the equal sign so the equation equals zero and add the (now negative) 12 to 4.
2. bring the 4y (don't forget to chance the negative to a positive) across the equal sign
3. then Divide both sides by the constant in front of the y (4 in this case). (put a 1 over the x and then the number you're dividing by next to the x).
4. Graph the equation, x=1, 2, 3, 4,....

Answer 6

first you need to solve for y

x - 4y + 4 = 12

subtract 4 from both sides

x - 4y = 8

then subract x from both sides

-4y = -x + 8

then divide both sides by -4

y = (1/4) x + 8

then use your equation so start your graph
use the formula y = mx + b

m = slope

and b equals the y intercept (what y equals when x is 0)

so draw a point at (0,8) (because b equals 8 so you know that when x equals 0 your y value is 8)

next use the slope (m) to figure out the next point

your slope is 1/4, so you want to go up (positive) one unit, and to the right (positive) 4 units. draw another point. connect the two points with a continous line with a ruler.

Answer 7

x-4y+4=12
x-4y=8(Subtracting 4 on both sides)
4y=x-8
y=x/4-2
now put this equation in a graphing calculator and if u don't have one do this..
the slope is 1/4 and the y intercept is -2 on the graph find -2 on y axis then go up by 1 unit on the y axis and then go to the right by 4 units plot that points go on doing that till the end of the graph
now come back to the point from where u started(-2 on y axis)
down by 1 and to the left by 4 go on doing that.
hope that helps..
the points will be(4,-1)(8,0)(12,1)(-4,-3)
(-8,-4)(-12,-5)....

Answer 8

x-4y+4=12
4y=x+4-12
4y=x-8
y=(1/4)x - 2

sketch y=x as a straight diagonal halfway between x and y axes. change the gradient of the slope to 1/4 of the gap between y=x and x-axis (half the gap then half it again to make it easier). then shift the line down 2 spaces.

Calculate points of intersection by making x and y 0:

when x is 0
y=-2

when y is 0
(1/4)x=2
x=8

So the points where the axes cross the line are (-2,0) and (8,0) at the y and x axes respectively. Method works for all linear equations.

Answer 9

First simplify your expression by getting y on on side of the equation all by itself:-4y=8-x

Next divide both sides by -4 so that all we have on the left is y:
y=-2+x/4
rewrite this as y=x/4-2 (same thing)
The negative two is where this line will cross the y-axis. The x/4 is the slope of the line (up 1 over four). So, from the point (0,-2) on the y-axis, go up four and over four to get another point on this line: then connect the two to make your line.

Answer 10

If you've completed 7th grade, this should be easy. I can only hope to God that you haven't.

x - 4y + 4 = 12
x - 4y = 8
-4y = 8 - x
4y = x - 8
y = x/4 - 2