A wheel has a radius of?

Question

.30 m and mass of 1.1 kg is rotating at 93.6 rad/s.

What torque is necessary to stop the tire in 1.72s in uits of N.m?

Answer 1

E=kinetic energy of wheel
r= radius of wheel
w=angular speed of wheel
m=mass of wheel
T=required torque
t=stopping time
W=necessary work to stop the wheel = E

E=m r^2 w^2
W=T * (w+0)/2 * t
E=W
T=2mw r^2/t
T=10.77 N.m

Answer 2

ok. do you want to find the slope for it .
you know gravity its 9.8m/s2
and you know (h) the hight and the mass.
so hxmxg= 30 x 1.1kg x 9.8m/s squre
no the slope is : 1/2 x mass x Vsqure.
so calculate it
and then N.m is like ( kg x m/s squre x m)
N.m is jole
so your resulte should be in m/s.
i hope it helps you.