What volume of carbon dioxide will be produced if 100 cm3 of 0.2M HNO3 is added to excess sodium carbonate?

Question

If you want 10 points b the 1st to answer this for me; thanks. :D

Answer 1

Na2CO3 + 2HNO3 → 2NaNO3 + H2O + CO2

0.1L * 0.2 mol/L = 0.02 mol HNO3

0.02 mole HNO3 * 1 mol CO2/2 mol HNO3 = 0.01 mol CO2

Now plug 0.01 mol CO2 into PV=nRT, using STP conditions.

PV=nRT

V = nRT/P

V = (0.01)(.0821)(298)/(1)

V = 0.24 L


*** The person above me did it WRONG! He confused sodium carbonate with sodium bicarbonate. Also, he completely forgot to do the stoichiometric conversions. He solved for moles of HNO3, and then plugged it into PV=nRT. You must first convert moles of HNO3 to moles of CO2 with stoichiometric conversions, using the BALANCED equation.

Answer 2

HNO3 + NaHCO3 ----> NaNO3 + H2O + CO2

number of moles of HNO3 = 0.1L * 0.2mol/L = 0.02 mol
means that there would also be 0.02 mol of CO2 produced
at STP, volume would be:

V=nRT/P = (0.02mol*0.08206L-atm/mol-K*298K)/1atm
V=0.489 L