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25cm3 of a solution of 0.2M of KOH reacts with 30cm3 of a solution of nitric acid. (KOH + HNO3 ---> KNO3+ H20)
My final answer was 4.1 mols dm3 of nitric acid/KNO3 is it correct?? :s plz help

2006-11-01 07:16:25 · 1 answers · asked by Joyce 4 in Science & Mathematics Chemistry

1 answers

KOH + HNO3 ---> KNO3+ H20

moles of KOH = 0.025L*0.2mol/L = 0.005 mol
concentration of nitric acid solution = 0.005mol/0.030L = 0.167M
concentration of KNO3 = 0.005mol/0.055L = 0.091M

2006-11-01 07:47:16 · answer #1 · answered by titanium007 4 · 0 0

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