How many pounds of candy selling for $1.75 a pound should be added to four pounds of candy selling for $3.99 a pound to create a blend, which will sell for $3.30 a pound?
** I got the answer but I'm not definite if it is right. If you solve this problem, please sbow me the equation and all the work... Thanks in advance.
2006-11-01 06:54:21 · 5 answers · asked by coolpowwow80 3 in Science & Mathematics ➔ Mathematics
1.75x+4*3.99=(4+x)*3.3
x=1.78
2006-11-01 07:06:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If candy A sells for $1.75/lb and candy B sells for $3.99/lb, a blend of x lb of A and 4 lb of B would sell in total for 1.75x + 4*3.99 = 1.75 + 15.96, and you'd have x + 4 pounds of it. The price per pound is therefore (1.75x + 15.96) / (x + 4). So (1.75x + 15.96) / (x + 4) = 3.30. Multiply both sides by (x + 4) to get 1.75x + 15.96 = 3.3x + 13.2. Then, just combine like terms and solve.
2006-11-01 15:00:06 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
Let x = weight of candy selling for $1.75/lb.
x + 4 = total weight of candy blend
Equation:
(1.75x + [4*3.99] ) / (x + 4) = 3.30
1.75x + 15.96 = 3.3x + 13.2
1.75x - 3.3x = 13.2 - 15.96
1.55x = 2.76
x = 1.78
Therefore, mass of the candy selling for $1.75/lb is 1.78 pounds.
2006-11-01 15:16:30 · answer #3 · answered by titanium007 4 · 0⤊ 0⤋
x*1.75+(1-x)3.99=3.30
-2.24x=-.69
x=.69/2.24=.308
Therefore, 30.8% of the mixed candy (by weight) should be the 1.75 per pound type.
Finally, y/(4+y)=.308
y=1.2320+.308y
.6920y=1.2320
y=1.7803 pounds must be added.
2006-11-01 15:02:48 · answer #4 · answered by bruinfan 7 · 0⤊ 0⤋
1.75x + 3.99y = 3.3(x+y)
y = 4
1.75x + 15.96 = 3.3x + 13.2
2.76 = 1.55x
x = 1.781 Lbs.
2006-11-01 15:09:14 · answer #5 · answered by Singing Ophelia 1 · 0⤊ 0⤋