limit (x^2+1)^3(2x+4)^2 / (3x^4+x^3)^2 = ?

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limit (x^2+1)^3(2x+4)^2 / (3x^4+x^3)^2 = ?

2006-11-01 06:10:19 · 3 answers · asked by Alireza G 1 in Science & Mathematics ➔ Mathematics

3 answers

What value does x approach? Without that information, there is no solution.

2006-11-01 06:16:52 · answer #1 · answered by jacinablackbox 4 · 0⤊ 0⤋

(x^2+1)^3(2x+4)^2 / (3x^4+x^3)^2=
=[x^2*(1+1/x^2)]^3*[2x*(1+4/(2x))]^2/[3x^4*(1+1/(3x)]^2=
=x^6(1+1/x^2)^3*(2*x)^2*(1+2/x)^2/[9x^8*[(1+1/(3x)]^2]=
=4*(1+1/x^2)^3*(1+2/x)^2/9/[(1+1/(3x)]^2=
=(4/9)*[(1+1/x^2)^3*(1+2/x)^2/[(1+1/(3x)]^2]= (at x>>1) =4/9
just check it!

2006-11-01 15:03:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋

We need more information here. What is x approaching?

2006-11-01 14:17:01 · answer #3 · answered by iuneedscoachknight 4 · 0⤊ 0⤋