solve by using the quadratic formula y = x2 - 6x + 8 = 0?

Question

solve by using the quadratic formula y = x2 - 6x + = 0

Answer 1

x = (-b +/- sqrt(b^2 - 4ac))/2a

where a= 1, b= -6 , c=8

x1 = (6 + sqrt(36 - 32))/2 = 4
x2 = (6 - sqrt4)/2 = 2

Answer 2

y = 0 and x = 2

Answer 3

y = x^2 - 6x + 8 = 0

y = (x-4)(x-2) = 0

the numbers in the brackets have toadd to -6 and multiply to 8

if x-4 = 0 and x-2 = 0 then x = 4 and x = 2

Answer 4

y = x2 - 6x + 8 = 0
can factor to get
(x-4)(x-2)=0
x=4
x=2

using the quadratic formula
x=(6+/-sqrt(36-32))/2=3+/-sqrt(4)/2
x=3+/-1
x=3+1=4
x=3-1=2

Answer 5

x^2 -6x+8 breaks down into (x-2)(x-4)=0, so x-2=0 and x-4=0

x=2,4

Answer 6

Well the quadratic equation is (-b+-sqrt(b^2-4ac))/2a where a = 1, b = -6 and c = 8.

Good luck. :)

Answer 7

y=x^2-6x+8

x^2-6x+8=0
(x-2)(x-4)=0
x=2 and 4

Check:
(2)^2-6(2)+8=0
4-12+8=0
-8+8=0
0=0

(4)^2-6(4)+8=0
16-24+8=0
-8+8=0
0=0

Answer 8

y=x2-6x+8=0
q.e=-b+-under root b2-4ac/2a
=6+-under root36-32/2
=6+-2/2
if it is +2 then answer is 4
if it is -2 then answer is 2

Answer 9

ax^2+bx+c=0
x=[-b+-sqrt(b^2-4ac)]/2a
y=x^2-6x+8=0
a=1
b=-6
c=8
x=[6+-sqrt(36-32)]/2
=[6+-2]/2
=3+-1
=4 or 2
verify
x=4
16-24+8=0 ok
x=2
4-12+8=0 ok

Answer 10

here a=1,b=6,c=8


answer is (6+sqrt(6*6-4*1*8))/(2*1) and (6-sqrt(6*6-4*1*8))/(2*1)

which comes to 4 and 2