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write the equation of the line containing the given point and having the given slope. Rewrite each equation in standard form with integral coefficients. Note: I am struggling emencly with how to do this.
(0,2), m=3.

2006-11-01 04:15:32 · 9 answers · asked by kris10 1 in Science & Mathematics Mathematics

9 answers

First, you use the point slope formula:
y-y1=m(x-x1)

y-2=3(x-0)
y-2=3x
y=3x+2

Standard form:
Ax+By=C

Subtract 3x on both sides:
-3x+y=2
That's your standard form!

2006-11-01 04:59:35 · answer #1 · answered by Anonymous · 4 1

Hmmm, if by "standard form", your prof means "point-slope form", the answer to the second part can be plugged into the equation:

y - y1 = m(x - x1)

which, in this case would be:

y-2 = 3(x-0)


Now to get the first part, the equation, you need y by itself on one side of the equal sign and everything else on the other. So multiply out the right side:

y - 2 = 3x - 0 = 3x

Now subtracting a negative 2 from both sides gives you:

y = 3x + 2,

which is also called "slope-intercept" form, which is:

y = mx + b.

[Note: b is the y-intercept of the line (where the line crosses the y-axis), and you already know that m is the slope, hence the name "slope-intercept" form.

Things are much easier when you remember these 2 different forms for what is called a linear equation. And just in case you're having problems with the "m", just remember, it is the slope, which is equal to the rise over run, which in this case is 3/1 = 3, right?. And since m = 3 in your question, it's very easy to find another point on the same line - just go up 3 and right 1 from (0,2), which puts you on the point (1,5).

2006-11-01 16:04:23 · answer #2 · answered by Gary H 6 · 2 0

The slope intercept form is

y = mx + b

And you know the slope, 3

y = 3x + b

Use the point (0, 2)

2 = 3(0) + b
b = 2

y = 3x + 2

Standard form

-3x + y = 2

2006-11-01 12:20:55 · answer #3 · answered by kindricko 7 · 3 1

When you are given a point on the y-axis, as your given point is (because x = 0), you can very easily use the slope-intercept form, y = mx + b. b is the y-intercept, which is the y-coordinate where the line crosses the y-axis, in this case 2 from the point you were given. m is the slope, which you were also given.

2006-11-01 12:19:24 · answer #4 · answered by DavidK93 7 · 3 1

y=mx+c is the equation of a line
in your case x=2, y=0
so 0=3*2+c
so c=-6
eqn is y=3x-6

2006-11-01 12:22:06 · answer #5 · answered by grandpa 4 · 0 3

y = mx + b

Use the point slope formula

y - y = m(x - x)

y - 2 = 3(x - 0)

y= 3x + 2

2006-11-01 12:16:43 · answer #6 · answered by Up_In_Smoke 2 · 1 3

y=mx+b
m=3
y=3x+b
2=3*0+b
b=2
y=3x+2

-3x+y=2
or
3x-y=-2

2006-11-01 13:15:04 · answer #7 · answered by yupchagee 7 · 2 1

Do your own homework. Pay attention in class, you might actually LEARN something.

2006-11-01 12:23:48 · answer #8 · answered by AzOasis8 6 · 1 1

y=mx+b where m is your slope and b is your height

2006-11-01 12:18:35 · answer #9 · answered by poker5495 4 · 1 3

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