The value of g at the Earth's surface is about 9.8N/kg^2...?

Question

What is the value of g at a distance from the Earth's center that is 4 times the Earth's radius?

Answer 1

acceleration due to gravity at a distance 4 times the radius is GM/(4R)^2 Where M is the mass of the earth . that is the answer is g/16.

Answer 2

Gravity law: 2 masses M & m are attracted to each other with force F=k*M*m/R^2, R being the distance between them, k – I don’t whose constant and how much it is.
If M is Earth’s mass and m is my mass and R is Earth’s radius then my weight F=m*g, that is m*g=k*M*m/R^2 or g=k*M/R^2. Now let me be 4 times R distant from Earth, then my weight be f=k*M*m/(4*R)^2, hence g(distant)=k*M/R^2/16=g(short)/16

Answer 3

The slithering of Christians/Muslims is astounding! Thee Bible/Koran talks with reference to the roundness of the earth which has to do with staring on the floor from the perfect of a hill or mountain the place you spot the panorama as being around no longer the rest. the reason of individuals believing in a flat earth got here from the former biblical e book "Enoch" which became removed from the Christian stimulated textile after a flat earth now no longer ought to be argued for. The so called primitive human beings, such because of the fact the Greeks no longer in easy terms knew the earth became around yet had calculated the circumference of the earth to a ultimate accuracy thinking what they had to artwork with. Christianity has been a stumbling block to information and humanity and attempting to curve it around is an insult!

Answer 4

We have the equation for object of mass m
at a dist 4R from the center of Earth.
mg=G*M*m/[4R]^2; G=universal const.,M=mass of Earth
g=G*M*/16R2
G=6.672*10^-11Nm^2kg^-2
M=6*10^24kg
R=7913/2 miles
=7913/2*1609.3 meters
=6367195.45m
substituting we have
g=6.672*10^-11*6*10^24/16*[6367195.45]^2 m/sec^2
=6.672*6*10^13/16*40.5*10^12
=0.0617*10
=.617m/sec^2

Answer 5

It goes down as r squared right ? Calculate it.

Answer 6

1/16 of 9.8 is 0.6125