Tricky Algebra???

Question

I used quadratic formula to solve.
find the x-intercepts: y=x^2-4x+4
At the end it works out to be 4+0=4/2=2
And then plus or negitve so 4-0=4/2=2
Answer x=2,x=2

Answer 1

When the term under the sqrt is zero, it means you have only *one* real root. The b² - 4ac is called the 'discriminant'.

You have correctly figured the answer which shows there is only one point where the parabola intercepts the x-axis and that point is (2, 0).

You are correct that the root is when x = 2.

Answer 2

yeah, so it only has one answer. it can also be factored to be (x-2)^2, and in that form you can see that x = 2 is the only answer.

Answer 3

So what's the question here? You did all the work right and got the right answers. So....

Answer 4

it is surely the Pythagorean theorem. ||x - y||^2 = = - - + = ||x||^2 + ||y||^2 - - using fact x is orthogonal to y, = = 0. for this reason, ||x - y||^2 = ||x||^2 + ||y||^2 Take the sq. root of the two sides to get ||x - y|| = ( ||x||^2 + ||y||^2 ) ^(a million/2).

Answer 5

y=x^2-4x+4
y=(x-2)^2
You are right!