2006-11-01 03:34:21 · 8 answers · asked by Andy P 1 in Science & Mathematics ➔ Mathematics
To differentiate y= 2/x
Firstly you get rid of the fraction by taking X to the top(this will make its power negative) giving:
y=2x^-1
From here its just a simple case of carrying out the differentiation:
dy/dx = -2X^-2 or dy/dx = -2/X^2
2006-11-01 04:44:59 · answer #1 · answered by Stevie B 2 · 0⤊ 0⤋
Think of it as 2x^-1
The differential is -2X^-2
2006-11-01 11:37:26 · answer #2 · answered by econdrone 2 · 1⤊ 0⤋
First step, put the expression in index form.
2/x = 2x^-1
Then differentiate as usual
dy/dx = -1 *2 x ^-1 -1
dy/dx = -2x^-2
It is usual to express the answer in the form of the question
dy/dx = -2/x^2
2006-11-01 11:39:11 · answer #3 · answered by RATTY 7 · 1⤊ 0⤋
In my head. I'd get -2/x^2.
2006-11-01 11:49:51 · answer #4 · answered by mathematician 7 · 0⤊ 0⤋
2/x = 2*x^-1
the derivative would then be:
(-1)*2x^(-1 - 1) = -2/(x^2) or -2x^(-2)
2006-11-01 11:36:47 · answer #5 · answered by disposable_hero_too 6 · 2⤊ 0⤋
y=2/x
y'=2(-1)/x^2=-2/x^2
2006-11-01 13:37:00 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
y=2/x=2*x^(-1)
y'=nx^(n-1)
therefore, y'=2*(-1)*x^(-2) = -2/x^2
i hope that this helps
2006-11-01 12:15:13 · answer #7 · answered by Anonymous · 0⤊ 0⤋
3 sq + 6.2x xy
2006-11-01 11:35:50 · answer #8 · answered by mannit m 4 · 0⤊ 2⤋