how to factor this problem?

Question

2x^2 -6x +3

Answer 1

2x^2-6x+3
use this formula
-b+or-root b^2-4ac/2a
In this case
a=2 b=-6 c=3
just substitute this value in above formula
Your answer must be
3+root3/2 3-root3/2

Answer 2

use factor therom.[ -b (+or-) (square root of) b^2 - 4.a.c ] / 2.a

;(since this does not factorise, your only choice is to use the formula.)

using ax^2+bx+c
so in your case.
a = 2
b= -6
c = 3

from this, you should see that your two answers are
[6+((root)(36-24))] / 2(2) ==> [3+(root)(3)]/2
[6-((root)(36-24))] / 2(2) ==> [3-(root)(3)]/2]

u should get 2.366025404
and 0.6339745962

or 2.37(3.s.f) or 0.634(3.s.f)
;which are the same as above

otherwise, most modern calculators can just work this out for you.

Answer 3

you can find the value of root x1,x2 then you will have this
( x - x1 ) ( x - x2 ) = 0