Math Help!!!! PLEASE HELP ME?

Question

please help me with my math I'm stuck!! even if you can only answer one it'll help alot thank you so much

1. What is the total area of a covered box with a length of 4 ft. , a width of 3 ft. and a height of 6 ft. ??




2. What is the lateral area of a right circular cone if the diameter of the base is 4 m and the slant height of the cone is 15 m?


3. What is the volume of a right pyramid whose base is a square with a side 6 m long and whose altitude is equal to the base side?


4. What is the lateral area of a right cylinder if the radius of the base is 12 mm and the altitude of the cylinder is 5 times the base radius?



5. What is the surface area of a cylindrical ring if its outside diameter is 16 mm and its inside diameter is 10 mm?

Answer 1

1. total area of a box of sides a,b,c is 2(ab+bc+ca)
a=4,b=3,c=6 => surface area = 108 sq.ft
..
2.Lateral area = pi*radius*slant ht
pi=3.1415,radius=2m(4m/2), slant ht=15m
ans is 188.49sq.metres
..
3. volume of pyramid = (1/3)* height * base area
= (1/3)* (6) * (6*6)
= 72 cu.metre
..
4. lateral area of cylinder = 2*pi* radius* height
=2*3.1415*12*60
=4523.76cu. mm
..
5. total surface area = outer surface + inner surface + top surface + bottom surface
= 2*pi*8*height + 2*pi*5*height + 2 times ( pi*(8-5)^2)
[the last term is the sum of top and bottom surfaces which are circular rings]
height is not given :(

Answer 2

Use the following formulas:

1. A = 2(lw + hl + hw)

2. A = pi rl (l = slant height)

3. A = 1/3 Bh = 1/3 s^3 (for B = s^2 and h = s)

4. Lateral A = 2 pi r h = 10 pi r^2 (for h = 5r)

5.

Let R = outside radius and r = inside radius

Area of two bases = 2 pi (R^2 - r^2)
Outer lateral area = 2 pi R^2 h
Inner lateral area = 2 pi r^2 h

Total area = 2 pi (R^2 - r^2 + R^2h + r^2 h)
A = 2 pi ( R^2 (h + 1) + r^2 (h - 1) )

I'm a bit confused though, since no height is given. It may be that you're just being asked for the area in two dimensions between two circles, in which case the formula is A = pi(R^2 - r^2).

Answer 3

we've continually pushed math and technology. not too puzzling I promise. even as my young children were about 4 we presented them to the idea of math by technique of creating them count number cookies or beans or notwithstanding they were eating. Then we would tell them they had to devour 5 huge bites of something or we would take a cookie away and then ask what number that they had left. For all you jerks accessible- NO we did not save the cookie we gave it decrease back. it really is in basic terms recommend. technology became particularly undemanding too. absolutely one of their fave technology initiatives became 2 empty coke bottles (a million 1/2 way crammed) taped at the same time, once you shake the bottles a particular way it made a twister. My oldest is into forensic technology. I swear that child can raise a finger print off something. My youngest loves plants so we use that to coach her about image voltaic and oxygen and so on, and so on.

Answer 4

1) area of box 108 square feet

2) area of cone 94.2 sq. meters

3) volume of pyramid 72 sq. meters

4) area of right cylinder 452.3 sq. mm

5) area of ring 76.43 sq. mm

1< area is sum of all 6 areas
6x3= 18,24,12 there are 2 of each
54x2= 108

2< area = pi (3.14159) x radius x height

3< vol= (base area x alt)/3

4< area= 2 x pi radius x alt

5< area of a ring is the area of the big circle minus the area of the little circle
area of circle is pi x rad squared, or .7854 x diameter

Answer 5

1. 2(4x3)+2(3x6) +2(4X6) =24+36+48=108 sq.ft
2. Pi x r x l = 3.14 x 2 x 15 = 30pi sq. m
Work the rest out youself!

Answer 6

why not pay attention at school and then you would know

Answer 7

1.12

Answer 8

Is this HOMEWORK!