There is a certain individual on this site who seems to be getting away with racist and insulting remarks. I have filled out the abuse form to yahoo countless times but nothing seems to have been done about him.
I think its bad enough to call someone a black bastard but to reply to practically every question going 'Shut up you retard' I think is now getting beyond a joke.
Last time I checked this was supposed to be a friendly forum, not a centre for abuse. QUESTIONER!!!!!!!! you know who you are!!!
This person may think his comments are funny. But listen in, A good friend of mine with mental health issues passed away this year and I find nothing entertaining, funny or 'its just a laugh' about this.!!
2006-11-01 00:37:10 · 7 answers · asked by bubble 2 in Society & Culture ➔ Other - Society & Culture
Thankfully a large majority of the people who use this site use it for the right reasons and ignore all of the arrogant twits who post useless information and comments. I'm not sure why nothing has been done though. Maybe there need to be multiple complaints from different people.
2006-11-01 00:42:20 · answer #1 · answered by Tallie 2 · 0⤊ 0⤋
Yahoo seems to be very selected in who they kick out of here.
2006-11-01 00:42:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋
yahoo seem to pick people at random to violate, don't know if they even read em
I got violated yesterday for asking which advert pissed you off the most
no rhyme or reason
2006-11-01 00:41:09 · answer #3 · answered by pepzi_bandit 2 6 · 0⤊ 0⤋
At yahoo homepage you'll find yahoo custom services...
2006-11-01 00:49:04 · answer #4 · answered by Anonymous · 4⤊ 0⤋
You just did by telling everyone
2006-11-01 00:39:40 · answer #5 · answered by babo1dm 6 · 1⤊ 0⤋
you just report as spam and ignore that person and report abuse and IGNORE his im's
2006-11-01 00:44:18 · answer #6 · answered by david j 5 · 0⤊ 0⤋
imagine if he called someone a retarded black bastard ! i bet that would really piss you off !
retard
2006-11-01 00:43:40 · answer #7 · answered by rileys_lad 1 · 0⤊ 2⤋