Solve this system of equations:
4x+3y=27
2x-y=1
2006-10-31 23:07:58 · 3 answers · asked by cocobarahorse 2 in Education & Reference ➔ Homework Help
4x + 3y=27
4x-2y = 2
now subtract the second equation from the first.
5 y = 25
y = 25/5 = 5
2x-5 = 1
2x = 6
x = 3
Test any of the two equation substituting values for x and y.
2006-10-31 23:21:06 · answer #1 · answered by LearningToLive 3 · 0⤊ 1⤋
4x+3y=27.....(eqn. no.1) 2x-y.=1...(eqn. no.2) Multiplying eqn, no.2 by 2,we get 4x-2y= 2 ...(eqn.no3) Subtracting eqn.no.3 from eqn.no.1 we get 5y=25 => y=25/5=5. Putting the value of y in equn,. no 1 we get 4x+3*5=27 =>4x+15=27 =>4x=27-15=12 =>x=12/4=3 Therefore x=3 and y=5 ans.
2006-11-01 09:08:23 · answer #2 · answered by alpha 7 · 0⤊ 0⤋
x=(y+1)/2
2*(y+1)+3y=27
5y=25
y=5
4x+15=27
x=3
...
2006-11-01 07:16:16 · answer #3 · answered by ╠╬╣ 3 · 0⤊ 1⤋