A 250 m long train is runnibg at the speed of 55km/h.In how much time will it cross a platform of 520m?
Hint:Distance travelled by train in crossing the platform=Length of the train=length of the platform.
2006-10-31 22:12:26 · 6 answers · asked by Dark angel 1 in Science & Mathematics ➔ Mathematics
speed = 55km/h = 275/18 m/s
distance 250 + 520 = 770m
time = distance/speed
= 770*18/275 Seconds
= 50.4 seconds
2006-10-31 22:19:03 · answer #1 · answered by Shantam M 2 · 0⤊ 0⤋
I'll see if I can do it without considering thre hint.
55km/h = 55*(5/18) m/s
= 275/18 m/s
= 15.2777777777777777...
= 15.27777778 m/s (approx)
It travels 15.27777778 meters in one second
Time taken to cross platform = Total distance/Speed of train
= (250 + 520)/15.27777778
= 770/15.27777778
= 50.399999999999... seconds
= 50.4 seconds (approx)
2006-11-01 06:32:54 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
It's almost been done for you. The hint tells you to add 250m and 520m, but since the speed is in km/h you should convert this distance to km.
Then use Time = distance/speed. Remember that will give you the time in hours, so you may wish to multiply by 60 to convert it to minutes.
2006-11-01 06:17:57 · answer #3 · answered by Hy 7 · 0⤊ 0⤋
t = (L(train) + L(platform))÷speed
= (0.25 + 0.52) ÷ 55
= 0.014 hours
= 50.4s
2006-11-01 06:22:20 · answer #4 · answered by 3.14 2 · 0⤊ 0⤋
kmph 55.00
meters per hour 55,000.00
meters per minute 916.67
total length 770.00 meters
Solution:
0.84000 minutes or,
0.01400 hours or,
50.40 seconds
2006-11-01 06:24:33 · answer #5 · answered by nalaka 2 · 0⤊ 0⤋
dark angel you must learn to imagine because without imagination there is nothing.
2006-11-01 09:07:32 · answer #6 · answered by Anonymous · 0⤊ 0⤋