The sum of three consecutive integers is 96. What is the integer.?

Answer 1

Let the three consecutive integers be 'x', 'x + 1' and 'x+2'
x + x+1 + x+2 = 96
3x + 3 = 96
3x = 96-3
3x = 93
x= 93/3
x = 31
The three consecutive integers are 31, 32 and 33.
Check the answer: 31 + 32 + 33 = 96
The answer is correct

Answer 2

Consecutive integers are only 1 away from each other. So, if you let the first integer be x, the second is x+1 and the third is x+2. Then, you know: x + x+1 + x+2 = 96, so 3x = 93, and x = 31. Therefore, the first integer is 31, and the next two are 32 and 33. Hope this helps!

Answer 3

let x = be the integer

(x-1) + x + (x +1) = 96

3* x = 96

x = 96/3 = 32

so the consecutive numbers are
31, 32, 33
Thus the integer is 32

Answer 4

This is an easy algebra problem. First you must find one of the numbers, we'll call the first one in the sequence N. Now all you have to do is solve the equation:
N + (N+1) + (N+2) = 96
simplify:
3N + 3=96
3N=93
Divide both sides by 3
N = 31

Now you know the first number in the sequence is 31, so the others are obviously 32 and 33 so:
31+32+33 = 96

Answer 5

Set it up like this:
x+x+1+x+2=96
3x+3=96
3x=93
x=31,32,and 33

Check:
31+31+1+31+2=96
93+3=96
96=96

Answer 6

31 + 32 +33 = 96

Answer 7

Three Consecutive Integers

Answer 8

(x-1)+ x + (x+1) = 96

3x = 96
x = 32

31, 32, 33 are three consecutive integers

Answer 9

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The sum of three consecutive integers is 96. What is the integer.?

Answer 10

n-1+n+n+1=96
3n=96
n=32

integers are 31, 32, 33