Categorization of this question was tough, and as there was no astrophysics subcat...
(assume his relative displacement on the surface of the planet is 0.)
2006-10-31 14:25:23 · 4 answers · asked by Scott R 6 in Science & Mathematics ➔ Astronomy & Space
also...........
http://answers.yahoo.com/question/index;_ylt=Aox87oWXVnJZ8sq_90LmJA7sy6IX?qid=20061031143426AAxqMbW
2006-10-31 14:26:22 · update #1
Accuracy to within the hour please......
2006-10-31 14:46:57 · update #2
This is kinda weird, because the sun is also rotating around the milky way and the milky way around the galactic cluser, which is moving as well, so if we completely neglect all of that. The number of days in a year is 365.242199, so you're talking about half a day early right now. So roughly 2 am (we're 2 years after the 2004 leap year and 2 years until the 2008 leap year), you could get more accurate by using that number, but I doubt you are looking for that accuracy.
2006-10-31 14:34:50 · answer #1 · answered by merlin692 2 · 2⤊ 0⤋
One answer is to plug in the b-day into Excel and add 42*365.242199, with the result of 4:08 pm 10/31/2006
2006-11-01 01:10:49 · answer #2 · answered by arbiter007 6 · 0⤊ 1⤋
If you believe that your friend was alive on 9/30 or on 8/31 then you have an immense problem on your hands. Want to open up the "when does life begin" issue?
2006-11-05 20:34:43 · answer #3 · answered by gone 7 · 0⤊ 0⤋
10/31, 6:08
2006-11-06 18:25:06 · answer #4 · answered by bentoro2001 1 · 0⤊ 0⤋