Ok I have a math problem that I cant find the answer to so here it is................?

Question

Find the integers that fit the following conditions:
*They are between 44 and 53
*The sums of their digets are prime
*They have more than three factors

Answer 1

We have 8 possibilities:
45,46,47,48,49,50,51,52
As the sum of the digits is prime, 47, 49, 50 and 52 are the only possibilities left.
The number(s) has/have more than 3 factors
47 can be safely eliminated as it is prime and has only two factors.
49 only has 3 factors : 1,7 and 49. So it is also eliminated
50 has 6 factors: 1,2,5,10,25 and 50. It is a candidate.
52 has 6 factors: 1,2,4,13,26 and 52. It is also a candidate.
Only 50 and 52 satisfy all the conditions.
Your integers are 50 and 52

Answer 2

Well the first statement limits the possibilities to 44 through 53.

The second leaves 47, 49, 50, and 52 as the only possibilites. You get this by adding the digits of the numbers from 44 to 53. For example to test 45, 4 + 5 = 9, which is not prime, so it is not a candidate for the answer.

47 is prime, so it is eliminated by the last statment. 49 has exactly three factors (1, 7 and 49) so it is also eliminated. 50 and 52 fit the criteria for the last statement. That's your answer.

Answer 3

Just by the middle rule we're down to:
47
49
50
52

47 is prime, so has only two factors, 49 has factors 1, 7 and 7.
50 has factors 1, 2, 5, and 5 and 52 has factors 1, 2, 2, and 13

Really, you have to count the duplicate factors to go over three. I'm guessing the answer is 50 and 52. Or there could be no such integer.

Answer 4

So what can't you do?
Do you know which integers are between 44 and 53? (There are 8 of them.)
Can you find the sums of their digits? (For 45, it would be 9.)
Can you tell whether a number is prime? (9 is not prime.)
Can you tell whether they have more than 3 factors? (The factors of 45 are 1, 3, 5, 9, and 15. That's 5 factors, so there are more than 3.)

Explain what you can't do, and we can help.

Answer 5

First conditions says:
The numbers can be 45, 46, 47, 48, 49, 50, 51 or 52
Second conditions constraints to:
47, 49, 50 or 52
Third condition eliminates 47 (prime) and 49 (only three factors - 1, 7, 49).
Hence the integers are 50 and 52.

Answer 6

This type of problem it is easiest to write out the and test them.
45: sum of the digits is nine(not a prime number)
46: sum of the digits is ten(not a prime)
47: sum of the digits is eleven(prime)
However 47 only has one factor being a prime number.
48: sum is 12(Out)
49: sum is 13(good)
However it only has two factors of 7
50: sum is 5 (good)
Factors down to 2*5*5
51: sum is 6( bad)
52: sum is 7 (good)
Factors down to 2*2*13
Since none fit the conditions your answer is the null set ( empty set there is no answer)