how do you solve this 2 ( 4 - 2r ) = -2 ( r + 5 ) ?

Question

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Answer 1

2 ( 4 - 2r ) = -2 ( r + 5 )
8 - 4r = -2r - 10
8 - 2r = -10
-2r = -18
r = 9

Answer 2

A: 2(4-2r) = -2(r+5)

B: (4-2r) = (r+5) {The 2’s cancel each other out)

C: 4 - 2r + r + 5 = 0 {Move the second part of the equation to the first and set the equation = to zero}

D: 9-r = 0 {4+5 = 9 and -2r + r = r

E: r = 9 {therefore, r = 9}

Answer 3

2 ( 4 - 2r ) = -2 ( r + 5 )
8 - 4r = -2r -10
-4r + 2r = -10 -8
-2r = -18
The minus signs cancel each other out.
2r = 18
r = 18/2
r = 9

Check the solution:
2[ - 2(9)] = -2( 9 + 5)
2(4 - 18) = -2(14)
2(-14) = -28
-28 = -28
As both sides are equal, the solution is correct.

Answer 4

Step by step.
1st distribute.
2(4-2r) = -2(r+5)
2x4-2x2r = -2xr- 2x5
8 - 4r = -2r - 10: Add 4r to both sides
8 - 4r + 4r = -2r + 4r -10
8 = 2r -10 : Now add 10 to both sides
8 + 10 = 2r - 10 + 10
18 = 2r : Divide both sides by 2
18/2 = 2r/2
9 = r

Answer 5

2(4-2r) = -2(r+5)
8-4r = -2r-10
-4r+2r = -10-8
-2r = -18
-2r/2 = -18/2
-r = -9
9 = r

Answer 6

2(4-2r) = -2(r+5)
8-4r = -2r-10
8+10 = -2r+4r
18 = 2r
r = 9

Answer 7

2 (4 - 2r) = - 2 (r + 5)
8 - 4r = - 2r - 10
-4r + 2r = - 10 - 8
- 2r = - 18
(-2r) / (- 2) = (-18) / (-2)
r = 9

Answer 8

2(4-2r)= -2(r+5) Divide by two on both sides.
4-2r = -(r+5) which is equal to 4-2r=-r-5
then add 5 to both sides 9-2r=-r
then subtract -2r from both sides 9=r

Answer 9

2(4-2r)=-2(r+5)=8-4r=-2r-10
=8+10=4r-(-2r
18 =6r
18/6r
=3r

Answer 10

open up the brackets
8-4r=-2r-10
take r term separate and numeric other side
8+10=4r-2r
18=2r
r=9 ans