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a. 11.82
b. 10.04
c. 3.44
d. 2.18
e. 0.80

2006-10-31 10:43:56 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

You need a Ka to solve that.

If you had the Ka...

Take the square root of (1x10^-14)*(1.75)/(Ka)
then take the log of that number and add 14.

2006-11-01 11:39:40 · answer #1 · answered by violet 4 · 0 0

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