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a. CO2
b. CaO
c. Mg(OH)2
d. NaBr
e. NaCH3CO2

2006-10-31 10:41:28 · 5 answers · asked by Anonymous in Science & Mathematics Chemistry

5 answers

a. CO2 forms carbonic acid in water (H2CO3)

2006-10-31 10:44:14 · answer #1 · answered by Anonymous · 0 0

This demands the calculation of pH of buffer answer for B) and C) . because of the fact which you have equimolar concentrations of the acid and its conjugate base , the pH will equivalent the pKa of the acid: n B) pKa CH3COOH = 4.seventy 4 pKa HNO2 = 3.4 D) is the salt of a vulnerable acid and robust base , so the pH would be approx 10.0. That leaves A) and C) you have considered that HNO2 has a decrease pKa than CH3COOH - so at equivalent molarity the HNO2 answer is extra acidic The score , from lowest to optimal pH is: a million) A) 0.10M HNO2 2) E) 0.10M CH3COOH 3) C) 0.10 M HNO2 and nil.10 M NaNO2 4) B) 0.10 M CH3COOH and nil.10 M CH3COONa 5) D) 0.10 M CH3COONa

2016-11-26 21:12:25 · answer #2 · answered by Anonymous · 0 0

CO2. It is a gas that will dissolve in water to form H2CO3 (carbonic acid, also called 'soda water').

All the other compounds will form basic solutions.

2006-10-31 10:47:31 · answer #3 · answered by Ecks 3 · 0 0

CO2 will form trioxocarbonate(V)acid when it react with water.such compounds form an acidic solution when they react with water are said to be an acid anhydride or acid former

2006-11-01 01:19:05 · answer #4 · answered by jayscanty 2 · 0 0

c

2006-10-31 10:43:39 · answer #5 · answered by D.P 3 · 0 1

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