go to indianproxy.com .. then once you have the site open . type what website you want to go to without the www or the http in it..thats what were using at work...we are not allowed to go to certain website.. we just type like multiply.com on the bar below and you can visit thats website anonymously...
2006-10-31 12:34:07
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answer #1
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answered by black.berries 2
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Circumventing information superhighway get correct of entry to regulate structures with internet proxies to get correct of entry to unauthorized internet internet sites is a contravention of school pc utilization coverage. you are able to get suspended and/or banned from utilising college pcs and community once you get stuck. Use college pcs for study, and orkut can wait till you get abode. Do you quite want your professors and faculty directors understanding what you submit on orkut in any case?
2016-12-05 10:02:47
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answer #2
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answered by aune 3
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Nope, I'm not going to tell you how to break your college's rules. If you've gotta get onto orkut, go off campus. Problem solved.
2006-10-31 10:24:36
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answer #3
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answered by Navigator 7
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SDA India Magazine ::News::List of The News
... a temporary fix in place and encourages Orkut users not to open suspicious files. ... anonymous creator when infected users click on the "My Computer" icon. ...sda-india.com/sda/news/psecom,id,9476,nodeid,1,_language,India.html
2006-11-02 22:48:47
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answer #4
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answered by Krishna 6
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hi u can use this site to open ur orkut.
.....http://anonymouse.org/anonwww.html
open this site and type ur site in that box it will open
2006-11-01 01:48:43
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answer #5
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answered by balu 1
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If your college is smart (and most aren't) about security a proxy won't help much.
2006-10-31 10:29:21
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answer #6
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answered by sjj571 4
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You need to be studying
2006-10-31 09:38:41
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answer #7
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answered by Anonymous
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Do your homework!
2006-10-31 10:11:09
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answer #8
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answered by * Deep Thought * 4
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https://proxify.com
just like that
Exaly like that.
2006-10-31 09:39:07
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answer #9
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answered by Cloud N 1
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try www.anonymizer.com
2006-10-31 09:39:00
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answer #10
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answered by jimjones3 4
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