25cm3 of a solution of 0.1M NaOH reacts with 50 cm3 of a solution of hydrochloric acid. What is the molarity of the acid?
2006-10-31 08:54:19 · 4 answers · asked by Joyce 4 in Science & Mathematics ➔ Chemistry
Wow, I happen to have stumbled upon another of your questions (which happens to be exactly the same as the one you posed earlier). As I said before, DO YOUR OWN HOMEWORK!
2006-10-31 08:57:54 · answer #1 · answered by BobRoberts01 5 · 1⤊ 0⤋
Check the solution I sent you for your H2SO4 question. Do it the same way, only the ratio will be 1 mole of acid for every 1 mole of NaOH this time. If you need further help, email calcu_lust@yahoo.com.
2006-10-31 17:02:05 · answer #2 · answered by calcu_lust 3 · 0⤊ 0⤋
1) V1 = 25 cm³ = 25 mL = 0.025 L
C1 = 0.1 M
V2 = 50 cm³ = 50 mL = 0.050 L
C2 = ?
2) We apply the following expression of neutralization:
C1V1 = C2V2
we solve for C2:
C2 = C1V1 / V2
C2 = (0.025 L)(0.1 M) / 0.050 mL
C2 = 0.05 M
So, the concentration of acid is 0.05 M
That´s it!
Good luck!
2006-10-31 17:13:23 · answer #3 · answered by CHESSLARUS 7 · 0⤊ 0⤋
With the given information, your question cannot be answered. Any amount of an acid will react with any amount of a base....with one or the other left over....maybe.....did the reaction occur to neutrality???
2006-10-31 17:43:05 · answer #4 · answered by Anonymous · 0⤊ 0⤋