25cm3 of sodium hydroxide react with 17cm3 of 0.1M of H2SO4.
Calculate the molarity of the sodium hydroxide.
The balanced equation is 2NaOH + H2SO4 ---->Na2SO4 + 2H2O.
so the ratio of the ............. NAOH to H2SO4 is 2:1 :D
2006-10-31 08:49:08 · 3 answers · asked by Joyce 4 in Science & Mathematics ➔ Chemistry
1cm^3 = 1mL =0.001 L
M=mol/L
So you have 0.1M sulfuric acid, and 0.017L of it. n=MV where M is molarity, n is number of moles and V is volume in Liters
You get 1.7x10^-3 moles of H2SO4.
So to neutralize that, you need twice as many NaOH's, so you need 3.4x10^-3 moles of NaOH to exist in that 0.025 L of solution:
M=n/V=3.4x10^-3 mol/ 0.025L = 0.136M solution of NaOH
2006-10-31 08:58:43 · answer #1 · answered by calcu_lust 3 · 0⤊ 0⤋
Yes I can do Chemistry calculations and you should do your own homework. Talk to your teacher or professor/TA about how to do it and you will learn a whole lot more than if we just give you the answer.
2006-10-31 16:52:55 · answer #2 · answered by BobRoberts01 5 · 0⤊ 0⤋
No, I can't do chemistry.
2006-10-31 16:50:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋