the diameter of each wheel of the bike is 26 in. if i was traveling at a speed of 35 mi/hr on the bike through how many revolutions per min are the wheels turning?
do i need to use s=r(beta)? and convert the 13in? thanks for the help.
2006-10-31 08:14:22 · 7 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics
35 mph = 35 * 63360 in / h
= 35 * 63360/ 60 in/min
= 36900 in/min
For each revolution the wheel travels πd in
ie 26π in
So angular velocity = 36900/26π
≈ 452.5 rpm
2006-10-31 08:27:55 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
If you were to cut the tire and lay it out flat you'd get one circumference forward for every revolution. Divide forway speed by circumference to get revolutions per time. By using circumference you'll be taking into account the diameter of the wheel.
2006-10-31 16:22:03 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
wow, you are bad at math... anyway, just find the circumference of the tire which is pi x diameter. from there, you should be able to work out the revolutions per minute.
2006-10-31 16:20:05 · answer #3 · answered by David W 4 · 0⤊ 0⤋
Hi. Circumference is Pi * 26. 35 MPH= .583 MPM (minute). Divide. No.
2006-10-31 16:19:45 · answer #4 · answered by Cirric 7 · 0⤊ 0⤋
For each revolution you will travel 26*pi inches. From here on it's all a matter of conversion:
35 miles per hour (some biker you are!)
= ? feet per hour
= ? inches per hour
= ? inches per minute
= ? revs per minute.
2006-10-31 16:17:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋
d=26"
c=pi*d=81.68"=6.81ft/rev
35mph*5280ft/mi/60min/hr=3080ft/min
3080ft/min/6.81ft/rev=452rpm
2006-10-31 16:21:04 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋