My textbook explains it incredibly disproportionatly. Can anyone please simply explain it to me?
Here's an example problem:
3x - 7y + 5 - 0
2006-10-31 08:10:42 · 5 answers · asked by Ryan 1 in Science & Mathematics ➔ Mathematics
The easiest way is to put your equation in slope/intercept form of:
y = mx + b
Then m = slope and b = y-intercept.
For example:
3x - 7y + 5 = 0
Now add 7y to both sides:
7y = 3x + 5
Divide both by 7:
y = (3/7)x + 5/7
So your slope (m) = 3/7 and the y-intercept (b) is 5/7.
2006-10-31 08:12:51 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋
3x - 7y + 5 - 0
the slope intercept form of an equation is
y=mx+b where m=slope & b=y intercept
3x - 7y + 5 - 0 add 7y to each side
3x+5=7y or
7y=3x+5
y=(3/7)x+5/7
slope=3/7
y intercept=5/7
2006-10-31 16:16:01 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
First you let the term with y in the first side of the equation and put the other terms in the other side:
-7y = -3x-5
Now you multiply every term by -1... that is change all the signals
7y = 3x + 5
Now you divide every term by 7 to obtain y
y = (3/7)x + 5/7
Now is all ready: 3/7 is the slope and 5/7 is the y-intercept
2006-10-31 16:18:51 · answer #3 · answered by vahucel 6 · 0⤊ 0⤋
Remember...
y = mx + b or A + B + C = 0
3x - 7y + 5 = 0
-7y + 5 = -3x
-7y = -3x -5
y = -3/-7x - 5/-7
y = 3/7x + 5/7
Slope is 3/7
y-int. is 5/7
(That's for y = mx + b)
3x - 7y + 5 = 0
Slope = -A/B
Slope = -3/-7 (3/7)
y-int. = -C/B
y-int. = -5/-7 (5/7)
2006-10-31 16:23:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
y=mx+b
2006-10-31 16:12:26 · answer #5 · answered by Me 6 · 0⤊ 0⤋