A security camera in a neighborhood bank is mounted on a wall 10 feet above the floor. What angle of depression should be used if the camera is to be directed to a spot 8 feet above the floor and 12 feet from the wall? (In other words, how far down should the camera be tilted?)
2006-10-31 08:09:50 · 6 answers · asked by beachbum 2 in Science & Mathematics ➔ Mathematics
Hi. It is a simple right triangle with the height 10-8=2 and the bottom 12.
2006-10-31 08:14:53 · answer #1 · answered by Cirric 7 · 0⤊ 0⤋
Draw a little sketch and label things. The wall makes a right angle with the floor. Angle of depression would be measured from the horizontal, which is parallel to the floor. When you get your sketch the way to solve it will jump out at you.
2006-10-31 08:16:00 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
if you draw it out you get a right triangle with the height =2 and length = 12.
The formaula for angle of depression is tanX = 2/12 where X= angle of depression.
Tan-1 (1/6) = X (Tan-1 = Tan inverse)
2006-10-31 08:19:08 · answer #3 · answered by jonathon.shine@rogers.com 2 · 0⤊ 0⤋
Build your right triangle, height = 2 (elevation difference between cam and object) and base = 12. Then use a little trig.
2006-10-31 08:14:07 · answer #4 · answered by Anonymous · 1⤊ 0⤋
you've the following a correct triangle inclusive of the tower, the floor, and the line between Erin and her father. the perspective of melancholy as considered by technique of Erin is an same because the perspective of elevation as considered by technique of her father. She seems down at him on an same perspective as he seems up at her. the perspective on the daddy is the perspective whose tangent is four hundred/2 hundred, an same because the perspective of melancholy at Erin.
2016-12-05 09:59:19 · answer #5 · answered by Anonymous · 0⤊ 0⤋
9.46 degrees
tan x = opposite/adjacent
2006-10-31 08:14:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋