an object is traveling around a circle with a radius of 5 cm. if in 20 sec a central angle of 1/3 radian is swept out, what is the angular speed of the object? what is its linear speed?
i know i have use s=r(beta), other than that, i'm at a lost. thanks for the help.
2006-10-31 07:41:01 · 3 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics
Angular speed = ω = β/t
=(1/3) / 20 rad/s
= 1/60 rad/s
v = rω
= 5 * 1/60 cm/s
= 1/12 cm/s
2006-10-31 08:12:50 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
angular speed = (1/3)/20 =1/60 rad/sec
linear speed = r*angular speed = 5 * (1/60) = 1/12 cm/sec
2006-10-31 07:53:26 · answer #2 · answered by sjv_ch 1 · 1⤊ 0⤋
1/3 radian in 20 sec=1 rad/min
linear speed =(1/(2*pi))rpm*2*pi*r cm/revolution=
2*pi*5^2/(2*pi)=25cm/mim
2006-10-31 07:46:40 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋