solution for equation of perpendicular bisector of a circle?

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solution for equation of perpendicular bisector of a circle?

2006-10-31 07:09:26 · 3 answers · asked by missyangel 1 in Science & Mathematics ➔ Mathematics

3 answers

Isnt any line that goes through the center a perpendicular bisector?

2006-10-31 07:10:44 · answer #1 · answered by E 5 · 0⤊ 0⤋

If the center of the circle is at (h, k) then any line passing through these coordinates (including x = h) is a bisector of the circle. But how do you mean 'perpendicular'? Perpendicular to what?

Doug

2006-10-31 07:19:51 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋

The equation for any line is:

y = mx + c

Given a circle with center at (x,y), if you solve for c, you can then plug in any slope (m) and have your line.

c = y - mx

Is this what you are looking for?

2006-10-31 07:15:24 · answer #3 · answered by Dave 6 · 0⤊ 0⤋