2006-10-31 06:59:13 · 11 answers · asked by Olaniyi s 1 in Science & Mathematics ➔ Mathematics
Technically, there are three cube roots of 8, but two of them are complex numbers. Both of them are irrational. But, the *real* cube root of 8 is 2, which is rational.
2006-10-31 12:13:55 · answer #1 · answered by mathematician 7 · 1⤊ 1⤋
No. Since 8=2*2*2=2^3, 8^(1/3)=2
2006-10-31 07:41:02 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
No, because the cube root of 8 is 2. (2x2x2=8) and 2 is a rational number because it can be turned into a fraction, by putting it over 1.
2006-10-31 07:13:23 · answer #3 · answered by Little Angel 2 · 0⤊ 0⤋
No
8 is the lowest number (except 1, any root of 1 = 1), that has a whole number, 2, as a cubic root. Any whole number is rational. The next number with a whole number as a cube root would be 27.
2006-10-31 07:09:47 · answer #4 · answered by corleone 6 · 0⤊ 0⤋
No
Cube root of 8 is 2.
2006-10-31 07:06:35 · answer #5 · answered by howlettlogan 6 · 0⤊ 0⤋
No, it's 2.
2006-10-31 07:43:08 · answer #6 · answered by Anonymous · 0⤊ 0⤋
2 is the cube root of 8
is 2 a rational number?
2006-10-31 07:01:27 · answer #7 · answered by dantheman_028 4 · 0⤊ 0⤋
8 is a perfect cube.
2006-10-31 07:01:21 · answer #8 · answered by modulo_function 7 · 0⤊ 0⤋
No. It's equal to 2, an integer, so rational.
2006-10-31 07:01:33 · answer #9 · answered by steiner1745 7 · 0⤊ 0⤋
No, the answer is 2.
2006-10-31 07:06:46 · answer #10 · answered by Black Mamba 2 · 0⤊ 0⤋