What is the index of refraction?

Question

An ray of light is incident on a block of transparent material with an angle of incidence of 42. The angle of refraction is 25 degrees. Use Snell's Law and remember that the index of refraction of air may be taken to be 1.00. (What equation do you use too?)(If it's possible, can you list the steps you took to get the answer?)THANKS!

Answer 1

Recall that Snell's law says that

ni * sin(qi) = nr * sin(qr),

where ni is the refractive index in the incident media, qi is the angle of incidence, nr is the refractive index of the transparent material, and qr is the angle of refraction. You can easily rearrange this equation to solve of the index of refraction (nr).

Answer 2

Snells Law says that (α_1)*sin(Θ_1) = (α_2)*sin(Θ_2) where the Θ's are the incident and refracted angles (from the normal) and the α's are the 'index of refraction' of the media. (Actually, the index of refraction is the ratio of the speed of light in a vacuum to the speed of light inside the media.) So, in your problem:
1*sin(42) = x*sin(25) or x = sin(42)/sin(25) = 1.583


Doug

Answer 3

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