2006-10-31 02:09:16 · 11 answers · asked by Amanda Fay! 3 in Science & Mathematics ➔ Mathematics
Whenever you come across this kind of problem, always distribute first.
5(2 + y) - 10y = 15
10 + 5y - 10y = 15
From here, you must collect like terms.
10 - 5y = 15
Bring the terms with variables to one side and the numbers on the other side.
-5y = 5
Divide by -5 to get y by itself.
y = -1
2006-10-31 02:16:54 · answer #1 · answered by blueorangerox618 2 · 0⤊ 0⤋
5*(2 + y) - 10y = 15
10 + 5y - 10y = 15
10 - 5y = 15 / - 10
-5y = 5 / : (-5)
y = -1
2006-10-31 10:19:22 · answer #2 · answered by Eiche666 1 · 0⤊ 0⤋
First of, there is no question here. You should have asked, solve for y or what is y.
Nway BODMAS tells us we open the bracket first. Where does that take us....10 + 5y - 10y = 15
Bring like terms together, -5y = 5
Divide both sides by 5
y = -1
2006-10-31 11:06:46 · answer #3 · answered by kenyanmartin2000 2 · 1⤊ 0⤋
5(2+y)-10y=15 divide by 5
2+y-2y=3 subtract 2 from each side
-y=1
y=-1
2006-10-31 12:02:10 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
10 + 5y - 10y = 15
- 5y = 5
y = -1
2006-10-31 10:17:28 · answer #5 · answered by manu_smartdude 2 · 0⤊ 0⤋
so... yeah, i know everyone else already answered this, but i just wanted to be cool like them cuz i luv math lol
5(2+y)-10y=15
10+5y-10y=15
10-5y=15
-5y=5
y= -1
sorry bout that lol
2006-10-31 10:46:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋
5(2+y)-10y=15
10+5y-10y=15
-5y=15-10
-5y=5
y=-1
2006-10-31 10:16:32 · answer #7 · answered by Anonymous · 0⤊ 0⤋
10+5y-10y=15
10-5y=15
-5y=5
y=-1
2006-10-31 10:34:33 · answer #8 · answered by Anonymous · 0⤊ 0⤋
5(2+y)-10y=15
10+5y-10y=15
-5y+10=15
-5y=15-10
-5y=5
y=5/-5
y=-1
2006-10-31 10:25:23 · answer #9 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
1) expand the 5(2+y) part.
2) add up the y's and the units.
3) do your homework!
2006-10-31 10:17:05 · answer #10 · answered by Anonymous · 0⤊ 1⤋