1mole of N2 is mixed with 3moles of H2 in a 4liter if 0.0025 mole of n2 is converted to NH3 by reaction?

Question

1mole of N2 is mixed with 3moles of H2 in a 4liter if 0.0025 mole of n2 is converted to NH3 by reaction N2+3H2 REVERSIBLE 2 NH3 CALCULATE THE equiliberium constant(K) in consentration units. What will be value of K for equiliberium 1/2N2+3H2 REVERSIBLE NH3

Answer 1

N2 + 3H2 <=> 2NH3

moles of N2 remaining at equilibrium: 1 - 0.0025 = 0.9975 mol
And concentration of N2 at equilibrium: [N2] = n/V = 0.9975/4 M

moles of H2 remaining at equilibrium: 3 - 3*0.0025 = 2.9925 mol
And concentration of H2 at equilibrium: [H2] = n/V = 2.9975/4 M

moles of NH3 produced: 2*0.0025 = 0.005 mol
And concentration of NH3 at equlibrium: [NH3] = n/V = 0.005/4 M

Equilibrium constant K = [NH3]^2/[N2]*[H2]^3

K = 1.34x10^(-4)

For the reaction: 1/2N2 + 3/2H2 <=> NH3

K' = square root(K) = square root(1.34x10^(-4)) = 1.157x10^(-2)

Answer 2

Remove Your Moles, Warts & Skin Tags in 3 Days
Easily, Naturally And Without Surgery

Answer 3

Stop cheating and do your own homework!