1mole of N2 is mixed with 3moles of H2 in a 4liter if 0.0025 mole of n2 is converted to NH3 by reaction?

Question

1mole of N2 is mixed with 3moles of H2 in a 4liter if 0.0025 mole of n2 is converted to NH3 by reaction N2+3H2 REVERSIBLE 2 NH3 CALCULATE THE equiliberium constant(K) in consentration units. What will be value of K for equiliberium 1/2N2+3H2 REVERSIBLE NH3

Answer 1

1) N2 + 3H2 <--> 2NH3

Keq = [NH3]^2/[N2][H2]^3

[N2] = 0.0025mol/4L = 0.000625 mol/L
[H2] = 0.0075mol/4L = 0.001875 mol/L
[NH3] = 0.005mol/4L = 0.00125 mol/L

Keq = (0.00125)^2/(0.000625)(0.00185...
= 3.79 x 10^5


2) 1/2N2+3H2 <---> NH3

Keq = (0.00125)/(0.000625)^1/2(0.001...
= 7.58 x 10^6

Answer 2

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