I need help solving these equations for x?

Question

y=ab/x
x=a^2+2a+1/(a+1)^2
y=abx

Answer 1

Answer 1:
y=ab/x
ab/x = y
b/x = y/a
1/x = y/ab
xy/ab = 1
xy = ab
x = ab/y

Answer 2:
x=(a^2+2a+1)/[(a+1)^2] (I suppose this is what you mean?)
x=(a^2+2a+1)/)a^2 + 2a + 1)
x = 1

Answer 3:
y=abx
abx = y
bx = y/a
x = y/ab

Answer 2

y=ab/x
x=a^2+2a+1/(a+1)^2
y=abx

y = y
ab/x = abx

1/x = x
x^2 = 1 either x=1 or x=(-1)

but see below

x=a^2+2a+1/(a+1)^2
x=(a+1)(a+1)/(a+1)^2
x=(a+1)^2/(a+1)^2
whatever value a, x=1

so the answer is
x=1

because x=(-1) not match with x=a^2+2a+1/(a+1)^2

conclusion
x=1

Answer 3

(1)y=ab/x
(2)x=a^2+2a+1/(a+1)^2
(3)y=abx
from (1) and (3) you will get
abx=ab/x
sqr(x)=1
ie; x=1

Answer 4

y=ab/x
xy=ab
x=ab/y

x=a^2+2a+1/(a+1)^2
This is already solved for x

y=abx
x=y/ab

Answer 5

1. x=ab/y
2. Seems to be already solved for x.
3. x=y/ab

Answer 6

x=ab/y
already solved for x
x=y/ab

Answer 7

equate 1,3 equations
ab/x = abx
ab gets cancel on both sibes
then we get

x^2 = 1
x=+/- 1

Answer 8

1.......x=ab/y
2..........alredy solved
3..........x=y/ab