When you have 2 unknowns (x and y), you must have at least 2 equations to resolve it, only one won't be enough, you can have hundreds answers (for example, x=2 and y=1 works, but it also works with x=1 and y=7/3, or y=2 and x=5/4 etc)
2006-10-30 23:33:51
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answer #1
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answered by julie c 3
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x = 2, and y = 1... 4 x 2 = 8+3 x 1 =11
2006-10-30 23:40:42
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answer #2
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answered by Boliver Bumgut 4
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4x +3y = 11
4x = 11-3y
y=1
4x = 11-3(1)
4x=8
x=2
x=2, y=1
x = 2, y = 1
x = 5, y = - 3
x = -4, y = 9
x =23, y=-27
2006-10-31 00:08:07
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answer #3
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answered by safrodin 3
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These linear equations in 2 variables can have many answers , so a few are :
when x = 2, y = 1
when x = 5, y = - 3
when x = -4, y = 9
2006-10-30 23:56:59
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answer #4
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answered by Enlightened 2
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4x+3y-11=0
x=2, y=1 satisfies the eq
2006-10-30 23:59:09
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answer #5
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answered by . 3
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In this equation, you have two unknowns (x and y) so you need two equations to solve it completely.
The incomplete solutions are:
Solving for x
4x = 11 - 3y
x = (11 - 3y)/4
Solving for y
3y = 11 - 4x
y = (11 - 4x)/3
2006-10-31 00:24:38
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answer #6
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answered by Loral 2
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if x = 0.5 and y = 3, then 4x +3y = 11 !
2006-10-30 23:32:30
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answer #7
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answered by kai Jie 1
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it cud be x=2 and y=1,well it satisfies the relation fine but having two unknowns in an expression and only one equation means that there cud be other values of x and y too.
2006-10-30 23:35:39
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answer #8
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answered by knocking_8_ur_door 1
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th sollution could be x=1, y=2
or x=2 , y=1
for the exact answer u gotta have to equtions for two unknowns
2006-10-31 00:21:54
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answer #9
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answered by silent rain 2
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x=2
y=1
4(2)+3(1)=11
8+3=11
I think but its been awhile
2006-10-30 23:29:22
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answer #10
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answered by betty boop 5
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