could you pls. explain?

Question

how do we solve expressions that contains dissimilar powers like these expressions:
4a^4b^2+a^2b-4
and
12a^3b^2-6a^2b+4a^2b^2-2ab

Answer 1

What you are asking isn't clear. You don't "solve" these, they are not equations. Do you mean simplify in some way? Maybe factorise?

Also, use some parentheses to clarify the expression, since this site doesn't seem to be able to use superscripts etc. e.g. I think for the first one you mean
4(a^4)(b^2) + (a^2)b - 4,

but you need to put the parentheses in to show what you mean.

If I've read the first one correctly, then I don't know what you can do with it. It could be seen as a quadratic expression:
4u^2 + u - 4 where
u = (a^2)b,

but you can't do anything with that -- it doesn't factorise.

The second expression has 2ab as a common factor, so you can write it as
2ab(6(a^2)b - ...etc.)

Answer 2

well it is quite obvious remove the 3b and replace with a 7 r.

Answer 3

Hit and Trial method.

Answer 4

4a^4b^2+a^2b-4
4(a^2b)(a^2b)+(a^2b)-4

and

12a^3b^2-6a^2b+4a^2b^2-2ab
12(a^2b)(ab) - 6(a^2b) +4(a^2b)(b)-2(ab)

subtitution
x = a^2b
y = ab
z = b

4(a^2b)(a^2b)+(a^2b)-4
4x^2+x-4 ...................................i)

12(a^2b)(ab) - 6(a^2b) +4(a^2b)(b)-2(ab)
12xy-6x+4xz-y ...........................ii)

4x^2+x-4=0
4x^2 + x = 4
x^2 + x/4 = 1
x= 0.882782

Answer 5

Hey mency.........I have a comment.

You are beautiful........and.............

this sum kinda sux!!

Answer 6

SORRY BABY - NEVER COULD DEAL WITH NUMBERS...