Mendel crossed a wild-type (round, yellow peas) pea plant to a pure breeding wrinkled green pea plant. He got 55 round yellow, 51 round green, 49 wrinkled yellow and 53 wrinkled green. What was the genotype of the two parents. Use your own nomenclature.
2006-10-30 16:38:18 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Biology
R = round
r = wrinkled
Y= yellow
y= green
RrYy (round, yellow) x rryy (wrinkled, green)
-----> 1:1:1:1 RrYy Rryy rrYy rryy
The parents were RrYy and rryy
(i.e. one was heterozygous for both traits and the other was homozygous recessive)
2006-10-30 17:20:49 · answer #1 · answered by ♪ ♫ ☮ NYbron ☮ ♪ ♫ 6 · 1⤊ 0⤋
as the ratio of F1generation obtained by mendel is roughly 1:1:1:1 &according to the traits studied by Mendel ,round & yellow are dominant traits so the genotype of parents is RrYy & rryy where symbols are as given by Mendel
2006-10-31 03:00:34 · answer #2 · answered by zia 1 · 0⤊ 0⤋
Rr Yy x rr yy
This way you get equal offspring frequencies.
2006-10-31 00:47:17 · answer #3 · answered by munkmunk17 2 · 0⤊ 0⤋
RR YY rr yy
2006-10-31 01:00:23 · answer #4 · answered by Mayank Sharma 2 · 0⤊ 0⤋
RRyy rrGG
2006-10-31 00:41:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋