Graph of Y=sin2x?

Question

I want to draw Y=sin2x in my graphpaper.But I can't identify Points to draw .If u know points of (x,y) to draw Y=sin2x nicely please give me (x,y) points with a .table.If it becomes difficult to draw table,you can send your data table to my e-mail address: [e-mail]. In (x,y) points X should be degrees and Y should be points.

Answer 1

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Answer 2

The points you should use are not "numbers" per se. You should use the main points of a unit circle (i.e. pi, etc.) This allows you to place the maximums, minimums and zeros accurately, which you couldn't do if you were using whole numbers. It would be a lot of estimation. Try using a unit circle to get main points.

Also, I mentioned maximums, minimum, and zeros.
Maximums- on a normal sin graph, the max y value will be 1, because you have a modified sin equation, you're answer will also be modified.
Minimums- normal sin graph will have a min of -1.
Zeros- These are the points where the graph crosses the x-axis. If you are using points from a unit circle, they will be even. If not, you're going to have long confusing decimals.

Answer 3

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RE:
Graph of Y=sin2x?
I want to draw Y=sin2x in my graphpaper.But I can't identify Points to draw .If u know points of (x,y) to draw Y=sin2x nicely please give me (x,y) points with a .table.If it becomes difficult to draw table,you can send your data table to my e-mail address: [e-mail]. In (x,y) points...

Answer 4

well, period is divided by B, which is 2
so the period is now Pi, divide that by 4, and you have the appropriate x values to graph with.

Answer 5

graphing calculators are a wonderful invention, you can pick one up at wal-mart...

Answer 6

you messed up