A person weighing 0.7 kN rides in an elevator that has a downward acceleration of 1.9 m/s^2. The acceleration of gravity is 9.8 m/s^2. What is the magnitude of the force of the elevator floor on the person? Answer in units of kN.
2006-10-30 15:43:11 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
An elevator that is ACCELERATING downward? Egad!
The downward acceleration makes it a simple proportion problem:
x / .7 = (9.8 - 1.9) / 9.8
2006-10-30 15:57:28 · answer #1 · answered by ? 6 · 0⤊ 0⤋
Weight (W) - Normal reaction force(N) = mass(m) X accelaration(a)
i.e.,
W - N = m X a
(0.7 X 10^3) - N = (0.7X10^3/9.8) X 1.9
(0.7X10^3) - ((0.7X10^3 X 1.9) / 9.8) = N
After calclating thi you will get the answer for your question ...
just make sure you get your brackets right, yeah?
2006-10-31 00:07:30 · answer #2 · answered by Sindhoor 2 · 0⤊ 0⤋