A person jumps from the roof of a house 4.6 m high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 m. The mass of his torso (excluding legs) is 46 kg. Find the average force exerted on his torso by his legs during deceleration.
2006-10-30 14:17:50 · 3 answers · asked by Emily J 1 in Science & Mathematics ➔ Physics
Does it matter? He's suicidal.
2006-10-30 14:26:02 · answer #1 · answered by OwNaGeR 3 · 0⤊ 1⤋
Well the way I did it, I found that it takes 0.969s for the feet to touch the ground, and at that point, the torso is moving down at a speed of 9.495m/s. To decelerate the torso to 0m/s ove 0.7m, the average acceleration is 64.4m/s^2 pointing up, and the average force F=ma is 2962.4N. Hope that's right
2006-10-30 14:34:29 · answer #2 · answered by magicice6 2 · 1⤊ 0⤋
g=9.14 m/s2 ???
2006-10-30 14:27:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋