English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2006-10-30 13:57:18 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

Take the common element out.
If you notice carefully there is a common element between 3x^8 and 15x^6. Can you tell me what?

yes, both have 3x^6 common. Now if you take this amout out from both your equation will be come

3x^6 ( x^2 - 5); (notice that 3x^6 * x^2 = 3x^8 and 3x^6 (5) = 15x^6)

Now if you want to further simplify this equation, you'll get
3x^6 (x+sqrt5)(x-sqrt5) (apply (a^2 - b^2) formula to (x^2 - 5)

2006-10-30 14:08:51 · answer #1 · answered by Cyber-Pal 2 · 0 0

Find the BIGGEST number that can go into 3 and -15 without a remainder.

How about 3 itself?

We can factor out 3 because 3 goes into 3 and -15 without a remainder.

NEXT:

How about the x terms?

X^6 can fit into X^8, too. How many times? X^6 goes into x^8
x^2 TIMES and into itself 1 time.

How did I get x^2, you may ask? I subtracted the exponents of the x terms.

What is 8 - 6? It's 2, right?

We factor out 3 and x^6 and divide each term left inside the parentheses by 3x^6.

Ready?

Here it is: 3x^6 (x^2 - 5)

Guido

2006-10-30 14:09:05 · answer #2 · answered by Anonymous · 0 0

easy:
first step,3x^8-15x^6=3x^6(x^2-5)=3x^6(x+square root of 5)(x-square root of 5)

2006-10-30 14:05:33 · answer #3 · answered by peterwan1982 2 · 0 0

the answer is (3x^6) times (x^2-5), sorry, i dont know how to explain that on the computer, i hope this helped

happy haloween!

2006-10-30 14:07:23 · answer #4 · answered by princess 2 · 0 0

3x^2(x^4 - 5x^3)

2006-10-30 14:00:43 · answer #5 · answered by Caffeinated 4 · 0 0

fedest.com, questions and answers