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A potted tree weighs 20 lbs. The pot is 2 lbs more than the tree. How much does the tree weigh without the pot?

2006-10-30 13:39:08 · 11 answers · asked by JOE M P 1 in Science & Mathematics Mathematics

11 answers

That's 3rd grade? Wow, things have sure progressed since I was a kid!

Anyhoo, the way you solve this is with a little algebra (not sure your 3rd grader will understand this, but let's give it a shot):

Tree = x
Pot = x+2

Tree+Pot = x + x + 2 = 20

So, 2x + 2 = 20
2x = 18
x = 9

So, tree (x) = 9 lbs, and pot (x+2) = 11 lbs.

~ ♥ ~

2006-10-30 13:40:42 · answer #1 · answered by I ♥ AUG 6 · 0 0

It weighs 9 pounds.

That's because, to put it in a thrid-graders terms, a pot weighs the same as the tree plus an extra two pounds. Therefore, you have to subtract 2 pounds from the overall of 20 lbs. That makes 18. Now, since both the pot and the tree should weigh the same, divide by 2 to find the weight of the tree: 9 lbs.

2006-10-30 21:41:55 · answer #2 · answered by Gimmip 2 · 0 0

What two numbers = 20 and are 2 numbers apart? 10 and 10 are equal, so 11 and 9 are the only obvious numbers, 11 +9 = 20 and 11 is two greater than 9.

2006-10-30 21:44:21 · answer #3 · answered by toosearch2 1 · 1 0

think algebra: if x is the weight of the tree then:
X + (X+2) = 20 lbs
so
2x + 2= 20
2X = 18
x = 9
the tree is 9 lbs
to check it, plug it back in 9 + (9+2) = 20, right?
there.

2006-10-30 21:59:03 · answer #4 · answered by kusainezumi 2 · 0 0

9 lbs

2006-10-30 21:42:53 · answer #5 · answered by Anonymous · 0 0

T + P =20
P = T+ 2


T = 9 lbs and P = 11 lbs.

2006-10-30 21:40:45 · answer #6 · answered by WildOtter 5 · 0 0

18 pounds

2006-10-30 21:48:14 · answer #7 · answered by jennalangdon 2 · 0 0

20 lbs.

2006-10-30 21:41:04 · answer #8 · answered by DJ Vendetta 3 · 0 2

x+(x+2)=20
2x+2=20
2x=18
x=9

2006-10-30 21:41:39 · answer #9 · answered by thierryinho 2 · 0 0

9 POUNDS AND 11 POUNDS. DON'T FEEL BAD, MY FATHER TRIES TO HELP MY SON BUT ONLY CONFUSES HIM.

2006-10-30 21:42:30 · answer #10 · answered by NETTA M 3 · 0 0

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