Goemetry question!!!!!!!!!!!!!!!!!!!! HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!?

Question

1 liter of paint can cover 22 square meters.how many liters are needed to to paint the smallest square that could contain the largest circle inside an equilateral triangle measuring 22 feet on one side? help me please

Answer 1

Okay... the first thing you need to do is take a few deep breaths, take out your graph paper, straight edge, protractor and compass and draw this object. If I'm reading this correctly -- this is a circle inscribed within a triangle and a square. Draw the triangle, inscribe the circle, then draw the square that inscribes the circle.

Also - are you sure the triangle is measuring 22 FEET, or is it 22 meters?

I'm sure there are other ways to solve this, but I do best with visuals, so I would draw the whole thing out first to scale.

Answer 2

If the triangle is 22 ft on a side, then the radius of the largest circle it can contain is 11*sqrt(3). The square that contains the circle is 22*sqrt(3) across and has an area that is [22*sqrt(3)]² = 22*22*3. (I won't multiply it out yet; you'll see why) So divide that by 22 m²/L and you get 66. But wait. You have a liter can of paint that covers square meters of area, but a triangle that's measured in feet. Was that a mistake? If both measurements are in meters, the answer is 66 L. But if you're serious about measuring the triangle in feet, then you'd better change the width of the square, 22*sqrt(3) meters, to feet before you square it.

Answer 3

Hi. The equilateral triangle has three 22 foot sides. The smallest circle will be tangent to the mid-point of each side of the triangle. The square will have all four sides equal to the circle's diameter. Convert to metric (unless feet was a typo) and there you go.