2006-10-30 13:07:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
im gonna split them up so its not so confusing
(x^-7)^-2 = x^14
(y^11)^-2 = y^-22
(z^14)^-2 = z^ -28
when u have a negative power, u can get rid of the negative by putting the whole thing into the denominator:
(x^14) (y^-22) (z^-28) =
(x^14) / (y^22) (z^28)
2006-10-30 13:10:28 · answer #1 · answered by Moo 4 · 0⤊ 0⤋
(x^-7y^11z^14)^-2 = x^(2*7) * y (-2*11) * z(-14 * 2) = x^14 * y^(-22) * z(-28)
2006-10-30 21:10:28 · answer #2 · answered by James Chan 4 · 0⤊ 0⤋
okay....this had better not be homework!!!
simplifying exponential expressions...
(x^-7)^-2 =x^14
(y^11)^-2=y^-22 or 1/(y^22)
and (z^14)^-2=z^-28 or 1/(z^28) (if i remember right, to simplify means no negative exponents)
so ~~~~~~~~~> x^14 / [y^22 * z^28]
2006-10-30 21:15:43 · answer #3 · answered by gggjoob 5 · 0⤊ 0⤋
x^14y^-22z^-28
x^14/(y^22z^28)
2006-10-30 21:10:51 · answer #4 · answered by dla68 4 · 0⤊ 0⤋