Reference Angles?

Question

Ok I know how to find reference angles... the angle from the x-axis and all but i don't understand this problem... it's online and i can check my answers right away ok so here it is

For each angle below, determine the quadrant in which the terminal side of the angle is found and find the corresponding reference angle.
theta=4
reference angle = ??? quadrant = 3

so that means 4 radians i get that. so thatwould be 360 degrees right? right. I have to tell what quadrant it's in and the only answer it took was quadrant 3... how is it in quadrant 3? And I don't know what the reference angle would be in radians.

Can anyone help me please =)

Answer 1

there are 3.14 radians in 180degrees ... each radian measure is 57.324 degrees
4 times that is 229.299degrees round to 229.3

229.3 is between 180 & 270 degrees , so it is in Q3
the reference is (229.3-180) or 49.3degrees

the reference to 49.3 in q3 is that cos&sin will be neg while tan is positive of the reference angle in Q1

cos(229.3) = -cos(49.3)
sin(229.3) = -sin(49.3)
tan(229.3) = tan(49.3)

Answer 2

Draw yourself a horizontal and a vertical axis. At the right end, write 0. At the top, write 90. At the left, write 180. At the bottom, write 270. All that is in degrees.

Draw the axes again, and this time number the ends 0, π/2, π, 3π/2. Understand that 4 radians is between π = 3.1416 and 3π/2 = roughly 4.5, which puts it in quadrant 3.

Answer 3

Snot 360; just over 180. Pi (3.14) r is 180, so 4 wuld be 4/pi*180 = 229 deg. Definitely in the 3rd quad.

Never heard the term "reference angle" before. Must be part of "new math".......!